General DiscussionAyy lmao

HAHAHAH SIN ScHWIIZER COUSIN HEISST BÜNZ LEE XD :gun:

>look on price of flights between prague and tokyo
>instantly get dotabuff ads based on that

guess i reached my final mmr

yeah ads are really scary, there was an experiment and apparently the facebook app on your phones listen 24/7

someone kept talking about catfood irl (simply repeating catfood), without having a cat or looking for catfood online, and a few days later he got catfood ads on fb)

LMAO Aimstrong

@spunki notice that each time u went core u won

COINCIDENCE? I THINK NOT!

u rly should instalock core and run down mid if u dont get it spunki!

someone kept talking about catfood irl (simply repeating catfood), without having a cat or looking for catfood online, and a few days later he got catfood ads on fb)

monkaX

good thing we're social cretins and dont have any meaningful social inetractions or hold any power whatsoever for corporations to use our phones data against us, right guys? :D :D :D

ye ure right i still don thave any friends stop reminding me of this

lmao

no friends in 2017 OMEGALÜL

i just lost a 20 min stomp as solo sup lich w/ jungle techies and 0/8 offlane and i feel absolutely nothing
the match before i was camped by bh and lost the lane to rubick mid while having 2 nulls, bottle and treads 15 mins in and i also felt nothing

untiltable? PogChamp

does anybody here know how to do these


if you know how to do it either write everything down step-by-step or do it on paper and take a picture ty

just turn the arrows so they point at each other, this should solve the equations.

arrows have nothing to do with equations Xd they are solvable even if they are in the wrong direction
ive done norton and thevenin circuits but theyre pretty hard idk if i can solve ill try tomororw

the shit isch zuu guet lmao

i had an exam which contained thevenin a week and a half ago
didnt get shit from that particular question

3558890264

With techies You will win unwinable battles

in normal skill? i think so too

i showed my grass the ayy lmao song, now i have weed

lmao my uni course has an online forum, and sometimes students go there and rage

then the prof comes and tells them tehyre c.unts, and the students come back on their knees apologizing

guys this was in my exam and i had a brainfart but im still not quite sure about the correct answer:
x1+x2-x3=1
2x1+3x2+ax3=3
x1+ax2+3x3=2
for which values of "a" does this system have 1) a unique solution, 2) no solutions and 3) infinitely many solutions (and find the solution set)?
it seems easy af but because the system is not homogeneous i cant figure out exactly what to do.

something something regular matrixes
i think

i dont remember how to determine how many solutions a system had(i only remember that if theres more equations(that aren't the same, i.e x+y=z|2x+2y=2z) than variables it has infinite solutions, and vice versa), but what prevents u from jut using gausses method to get a triangular matrix and go from there?

here u go sir https://matrixcalc.org/en/slu.html#analyse-compatibility%28%7B%7B1,1,-1,1%7D,%7B2,3,a,3%7D,%7B1,a,3,2%7D%7D%29

god bless the creator this site

anybody got an idea how to solve these?

(1.b) determine the amount of partial relations on [4], on which there are 2 minimal elements.

(2.b) give equivalence relations R, S ⊆ A × A , so that R ∪ S is no longer an equivalence relation.

------------

R ⊆ A × A is a binary relation

(4.a) prove that R* is transitive and reflexive

(4.a2) prove that if S ⊆ A × A is a reflexive and transitive relation with R ⊆ S, then R∗ ⊆ S.

(2.b) give equivalence relations R, S ⊆ A × A , so that R ∪ S is no longer an equivalence relation.

A={1, 2, 3} R={(1, 2), (2,1)}, S={(1, 3), (3, 1)}

o shit i thought id have to make the 2 equivalence relations form one partial relation which doesnt work (i think)

thanks

u got any idea for 1b? [4] equals {1,2,3,4}

what is a partial relation

maybe it's just potency set of [4] minus the relations [1,1];[2,2],[3,3],[4,4] so it's not reflexive?

i'm probably wrong but there might be something that could help

partial relations are antisymetrical, reflexive and transitive

i.e. ≤Z, |N, ⊆

=< would look like this

okay wiki said that partial relations are symmetric and transitive
nevermind

we have another term for this kind of relation but there's just a czech version of it on wiki, not english or anything else

i dont know what the rest of the tasks want from u

i don't know how to solve 1b except with brute force
is that solution ok for you?

hmmm potency set seems fine but im not sure, i'll talk to my group tomorrow anyway so theres no need for u to do any work, but thanks

@alenari what part do u not understand?

ignore the first post, i misunderstood the partial relations

1b)
use hasse's diagrams.
draw all possible diagrams for 1 element, 2 elements, then for 3, then for 4.
and for every diagram containing n elements add n! because there's n! (i hope?) (4!/(4-n)!) options to put the elements into the diagram

hasses diagrams are for domination(?) relations not partial relation, i dont think they will help here anyhow

no, we use hasse for partial relatiosn as well

maybe partial = domination in ur language? i never heard of domination relations

partial relations are antisymetrical, reflexive and transitive

also i believe that my solution of the 1b is correct, i can draw the possible diagrams as well if you want me to.